以下哪个函数调⽤会返回 [2, 4, 6]？ ( )
def process(lst, func):
return [func(x) for x in l st]
nums = [1, 2, 3]
process(nums, lambda x: x % 2)
process(nums, lambda x: x + 1)
process(nums, lambda x: x ** 2)
process(nums, lambda x: x * 2)